2x^2+130x-4000=0

Solution for 2x^2+130x-4000=0 equation:

2x^2+130x-4000=0

a = 2; b = 130; c = -4000;
Δ = b2-4ac
Δ = 1302-4·2·(-4000)
Δ = 48900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48900}=\sqrt{100*489}=\sqrt{100}*\sqrt{489}=10\sqrt{489}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(130)-10\sqrt{489}}{2*2}=\frac{-130-10\sqrt{489}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(130)+10\sqrt{489}}{2*2}=\frac{-130+10\sqrt{489}}{4}
$